9x^2-3x-3x+1=25

Solution for 9x^2-3x-3x+1=25 equation:

9x^2-3x-3x+1=25

We move all terms to the left:

9x^2-3x-3x+1-(25)=0

We add all the numbers together, and all the variables

9x^2-6x-24=0

a = 9; b = -6; c = -24;
Δ = b2-4ac
Δ = -62-4·9·(-24)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-30}{2*9}=\frac{-24}{18}
=-1+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+30}{2*9}=\frac{36}{18}
=2
$